(5a/4)^2+62a+672=0

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Solution for (5a/4)^2+62a+672=0 equation:



(5a/4)^2+62a+672=0
We add all the numbers together, and all the variables
(+5a/4)^2+62a+672=0
We add all the numbers together, and all the variables
62a+(+5a/4)^2+672=0
We multiply all the terms by the denominator
62a*4)^2+(+5a+672*4)^2=0
We add all the numbers together, and all the variables
62a*4)^2+(5a+2688)^2=0
We add all the numbers together, and all the variables
62a*4)^2+(5a=0
Wy multiply elements
248a^2=0
a = 248; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·248·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{496}=0$

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